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0): #We actually got some rows. echo "
\n
\n"; for($i = 1; $i <= $NUMPAGES; $i++): #loop to print << 1 2 3... $NUMPAGES >> if($i == 1 && $PAGE > 1) #Prints the << first to goto the previous page (not on page 1) echo "
«
"; if($i == $PAGE) #Doesn't print a link itself, just prints page number echo "
$i
"; if($i != $PAGE) #Other links that aren't this page go here echo "
$i
"; if($i == $NUMPAGES && $PAGE != $NUMPAGES) # Link for next page >> (not on last page) echo "
»
"; endfor; echo "
\n
\n"; echo "
\n"; $START = ($PAGE - 1) * $DISPPAGE; mysql_data_seek($QRETURN,$START); #Moves the pointer to right row #This loop will go until you a) reach $DISPPAGE or b) there aren't anymore entries for($i = 1; $i <= $DISPPAGE && $ARET = @mysql_fetch_array($QRETURN); $i++): $VAR = $ARET["col"]; #******** Here's the bit you should update! ********# echo "$VAR\n
\n\n"; #echoes the field... # Alternately, if you feel like numbering. I haven't tested this. #echo "
".$START + ($i - 1)."
: $VAR\n
\n\n"; endfor; echo "
\n"; endif; if($QNUM == 0) #if we get no rows echo "
The database is empty
\n"; endif; if(!$QRETURN): # Bogus Query, or mysqld isn't running... echo "
\n"; echo "
\n"; echo "Either the database is down, or the query was invalid\n"; echo "
\n
\n"; endif; ?>
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